0=-4.9t^2-2t+950

Solution for 0=-4.9t^2-2t+950 equation:

0=-4.9t^2-2t+950

We move all terms to the left:

0-(-4.9t^2-2t+950)=0

We add all the numbers together, and all the variables

-(-4.9t^2-2t+950)=0

We get rid of parentheses

4.9t^2+2t-950=0

a = 4.9; b = 2; c = -950;
Δ = b2-4ac
Δ = 22-4·4.9·(-950)
Δ = 18624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18624}=\sqrt{64*291}=\sqrt{64}*\sqrt{291}=8\sqrt{291}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8\sqrt{291}}{2*4.9}=\frac{-2-8\sqrt{291}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8\sqrt{291}}{2*4.9}=\frac{-2+8\sqrt{291}}{9.8}
$